之前的两篇文章:Java实现两人五子棋游戏(二) 画出棋盘;Java实现两人五子棋游戏(三) 画出棋子;Java实现两人五子棋游戏(四) 落子动作的实现;Java实现两人五子棋游戏(六) 行棋方变换,可以点击查看。

接下来我们要实现的功能是在有五连珠的时候,在屏幕上提示信息。直接在mousePressed函数的isWin部分使用showMessageDialog即可。
mousePressed函数代码如下:
@Override
//当用户按下鼠标按钮时发生
public void mousePressed(MouseEvent e) {
int point_x=e.getX();
int point_y=e.getY();
int imgWidth = boardImg.getHeight(this);
int imgHeight = boardImg.getWidth(this);
int FWidth = getWidth();
int FHeight= getHeight();
int x=(FWidth-imgWidth)/2;
int y=(FHeight-imgHeight)/2;
int span_x=imgWidth/ROWS;
int span_y=imgHeight/ROWS;
//System.out.println("press");
int status_x = 0;
int status_y = 0;
if(point_x>=x && point_x<=x+imgWidth && point_y>=y && point_y <= y+imgHeight)
{
//System.out.println("合法");
for(int i=0;i=x-chessman_width/2+1+i*span_x)
{
if(point_x<=x+chessman_width/2-1+i*span_x)//如果是width/2会在中间点出现两个匹配值
{
//System.out.println("point x "+i+" "+point_x+" "+(x-chessman_width/2+i*span_x)+" "+(x+chessman_width/2+i*span_x));
status_x = i;
}
}
}
for(int i=0;i=y-chessman_width/2+1+i*span_y)
{
if(point_y <= y+chessman_width/2-1+i*span_y)
{
//System.out.println("point y "+i+" "+point_y+" "+(y-chessman_width/2+1+i*span_y)+" "+(y+chessman_width/2-1+i*span_y));
status_y = i;
}
}
}
if(chessStatus[status_x][status_y]==null||chessStatus[status_x][status_y].getPlaced()==false)
{
Chessman chessman = new Chessman(chessColor, true);
chessStatus[status_x][status_y]=chessman;
System.out.println("chess color:"+chessColor);
if(chessColor==BLACK)
{
chessColor = WHITE;
}else {
chessColor = BLACK;
}
repaint();
//如果胜出,给出提示信息
if(isWin(status_x, status_y, chessStatus))
{
System.out.println("WIN!!!!!");
String winner;
//如果下一子是白色的,那么此次为黑方
if(chessColor == WHITE)
winner = "黑方";
else
winner = "白方";
String mString = String.format("恭喜,%s WIN!!!!!", winner);
JOptionPane.showMessageDialog(this, mString);
}
}
}
}