这篇文章主要为大家展示了Python怎么防止死锁,内容简而易懂,希望大家可以学习一下,学习完之后肯定会有收获的,下面让小编带大家一起来看看吧。

问题
你正在写一个多线程程序,其中线程需要一次获取多个锁,此时如何避免死锁问题。
解决方案
在多线程程序中,死锁问题很大一部分是由于线程同时获取多个锁造成的。举个例子:一个线程获取了第一个锁,然后在获取第二个锁的 时候发生阻塞,那么这个线程就可能阻塞其他线程的执行,从而导致整个程序假死。 解决死锁问题的一种方案是为程序中的每一个锁分配一个唯一的id,然后只允许按照升序规则来使用多个锁,这个规则使用上下文管理器 是非常容易实现的,示例如下:
import threading
from contextlib import contextmanager
# Thread-local state to stored information on locks already acquired
_local = threading.local()
@contextmanager
def acquire(*locks):
# Sort locks by object identifier
locks = sorted(locks, key=lambda x: id(x))
# Make sure lock order of previously acquired locks is not violated
acquired = getattr(_local,'acquired',[])
if acquired and max(id(lock) for lock in acquired) >= id(locks[0]):
raise RuntimeError('Lock Order Violation')
# Acquire all of the locks
acquired.extend(locks)
_local.acquired = acquired
try:
for lock in locks:
lock.acquire()
yield
finally:
# Release locks in reverse order of acquisition
for lock in reversed(locks):
lock.release()
del acquired[-len(locks):]